Adams moulton ODE
Consider an ordinary differential equation
(dy/dt) = 0.5y - 2.5sin(t), 0
for the function y(t) with the initial condition y(0) = 2
-Derive equations for Adams-Moulton three-step method applied to this
problem. Provide an expression for the value of the approximate solution
wi+1 at a timestep ti+1 in terms of previously calculated values. Take
required starting values from the exact solution y(t) = 2cos(t)sin(t).
Provide the starting values.
-Write a Matlab code implementing the method for this problem. Provide the
text of the code.
If someone could provide the answers, I'd be grateful. Thanks.
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